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A344178
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Difference between the arithmetic derivative of n and the cototient of n: a(n) = A003415(n) - A051953(n).
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2
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0, 0, 0, 2, 0, 1, 0, 8, 3, 1, 0, 8, 0, 1, 1, 24, 0, 9, 0, 12, 1, 1, 0, 28, 5, 1, 18, 16, 0, 9, 0, 64, 1, 1, 1, 36, 0, 1, 1, 44, 0, 11, 0, 24, 18, 1, 0, 80, 7, 15, 1, 28, 0, 45, 1, 60, 1, 1, 0, 48, 0, 1, 24, 160, 1, 15, 0, 36, 1, 13, 0, 108, 0, 1, 20, 40, 1, 17, 0, 128, 81, 1, 0, 64, 1, 1, 1, 92, 0, 57, 1, 48, 1, 1, 1, 208
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OFFSET
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1,4
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COMMENTS
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Answer: Yes, can be proved when n = Product_{i=1..k} p_i^e_i with n' = n * Sum_{i=1..k} (e_i/p_i) and cototient(n) = n * (1 - Product_{i=1..k} (1 - 1/p_i).
a(n) = 0 iff n is in A008578 (1 together with the primes).
a(n) = 1 iff n is in A006881 (squarefree semiprimes) (End).
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LINKS
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FORMULA
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MATHEMATICA
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Array[If[# < 2, 0, # Total[#2/#1 & @@@ FactorInteger[#]]] - # + EulerPhi[#] &, 96] (* Michael De Vlieger, May 24 2021 *)
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PROG
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(PARI)
A003415(n) = if(n<=1, 0, my(f=factor(n)); n*sum(i=1, #f~, f[i, 2]/f[i, 1]));
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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