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A262619
Number of parts in the symmetric representation of sigma(n) in two successive octants of two quadrants.
3
1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 3, 1, 1, 1, 3, 1, 3, 1, 1, 1, 1, 1, 3, 1, 3, 1, 1, 1, 3, 1, 1, 1, 1, 1, 3, 1, 1, 1, 3, 3, 3, 1, 1, 1, 3, 1, 3, 1, 1, 1, 1, 1, 5, 1, 3, 1, 1, 1, 3, 3, 1, 1, 1, 1, 3, 1, 3, 1, 1, 1, 5, 1, 1, 1, 3, 1, 3, 1, 1, 1, 3, 1, 3, 1, 3, 1, 1, 3, 5, 1, 1, 1, 1, 1, 3, 1
OFFSET
1,9
COMMENTS
In the diagram of the top view of the pyramid described in A244050 consider a 90-degree sector on two successive octants of two quadrants. The area of the top triangle is equal to 1 and the sum of the areas of all parts (or regions) added at n-th stage equals sigma(n), the sum of the divisors of n.
a(n) is also the number of terraces at n-th level (starting from the top) in the mentioned sector of the pyramid.
For more information see A237593 and A237270.
LINKS
Antti Karttunen, Table of n, a(n) for n = 1..5000 (computed from the b-file of A237271 provided by Michel Marcus)
FORMULA
a(n) = A237271(n), if A237271(n) is odd.
a(n) = A237271(n) - 1, if A237271(n) is even.
KEYWORD
nonn
AUTHOR
Omar E. Pol, Nov 06 2015
STATUS
approved