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A224996
Floor(1/f(x^(1/n))) for x = 2, where f computes the fractional part.
3
2, 3, 5, 6, 8, 9, 11, 12, 13, 15, 16, 18, 19, 21, 22, 24, 25, 26, 28, 29, 31, 32, 34, 35, 37, 38, 39, 41, 42, 44, 45, 47, 48, 49, 51, 52, 54, 55, 57, 58, 60, 61, 62, 64, 65, 67, 68, 70, 71, 73, 74, 75, 77, 78, 80, 81, 83, 84, 86, 87, 88, 90, 91, 93, 94, 96, 97
OFFSET
2,1
COMMENTS
First denominator of continued fraction representing 2^(1/n): [1,a(n),....] so that 1+1/a(n) is first convergent for 2^(1/n). - Carmine Suriano, Apr 29 2014
LINKS
Melvyn B. Nathanson, On the fractional parts of roots of positive real numbers, Amer. Math. Monthly, 120 (2013), 409-429.
FORMULA
a(n) = floor(n/log(2)-1/2). - Andrey Zabolotskiy, Dec 01 2017
MATHEMATICA
th = 2; t = Table[Floor[1/FractionalPart[th^(1/n)]], {n, 2, 100}]
KEYWORD
nonn,easy
AUTHOR
T. D. Noe, Apr 26 2013
STATUS
approved