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A078358 Complementary numbers to A002378. 12
1, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 15, 16, 17, 18, 19, 21, 22, 23, 24, 25, 26, 27, 28, 29, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 73, 74 (list; graph; refs; listen; history; internal format)
OFFSET

1,2

COMMENTS

The (primitive) period length k(n)=A077427(n) of the (regular) continued fraction of (sqrt(4*a(n)+1)+1)/2 determines whether or not the Diophantine equation (2*x-y)^2 - (1+4*a(n))*y^2 = +4 or -4 is solvable and the approximants of this continued fraction give all solutions. See A077057.

The following sequences all have the same parity: A004737, A006590, A027052, A071028, A071797, A078358, A078446. - Jeremy Gardiner (jeremy.gardiner(AT)btinternet.com), Mar 16 2003

Infinite series 1/A078358(n) is divergent. Proof: Harmonic series 1/A000027(n) is divergent and can be distributed on two subseries 1/A002378(k+1) and 1/A078358(m). Becuase infinte subseries 1/A002378(k+1) is convergent to 1 that mean that Sum[1/A078358(n),{n,1,Infinity}] is divergent. [From Artur Jasinski (grafix(AT)csl.pl), Sep 28 2008]

REFERENCES

O. Perron, "Die Lehre von den Kettenbruechen, Bd.I", Teubner, 1954, 1957 (Sec. 30, Satz 3.35, p. 109 and table p. 108).

FORMULA

4*a(n)+1 is not a square number.

a(n) = ceiling(squareroot(n)) + n -1. - Leroy Quet Jul 06 2007

MATHEMATICA

Complement[Range[930], Table[n (n + 1), {n, 0, 30}]] (* and *) Table[Ceiling[Sqrt[n]] + n - 1, {n, 900}] (* From Vladimir Joseph Stephan Orlovsky, Jul 20 2011 *)

CROSSREFS

a(n)=(A077425(n)-1)/4.

A144786 [From Artur Jasinski (grafix(AT)csl.pl), Sep 28 2008]

Sequence in context: A039177 A058986 A184431 * A175968 A152012 A173153

Adjacent sequences:  A078355 A078356 A078357 * A078359 A078360 A078361

KEYWORD

nonn,easy

AUTHOR

Wolfdieter Lang (wolfdieter.lang(AT)physik.uni-karlsruhe.de), Nov 29 2002

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Last modified February 17 19:13 EST 2012. Contains 206085 sequences.