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A397030
Decimal expansion of Sum_{k>=1} H(k) / (2*k+1)^4, where H(k) = A001008(k)/A002805(k) is the k-th harmonic number.
4
0, 1, 6, 2, 4, 0, 6, 5, 7, 8, 5, 0, 2, 3, 5, 7, 0, 3, 0, 9, 5, 1, 2, 8, 3, 7, 2, 9, 0, 5, 5, 5, 2, 2, 3, 5, 8, 1, 3, 0, 0, 3, 8, 8, 6, 8, 0, 5, 6, 1, 9, 0, 3, 7, 3, 1, 9, 6, 8, 1, 0, 3, 2, 4, 2, 0, 7, 9, 7, 0, 4, 7, 0, 1, 0, 0, 1, 1, 8, 9, 0, 9, 2, 2, 4, 9, 2, 5, 4, 1, 2, 2, 7, 4, 6, 5, 8, 0, 9, 3, 9, 4, 0, 3, 6
OFFSET
0,3
LINKS
Ross C. McPhedran and David H. Bailey, New Results for Euler Sums, arXiv:2311.06294 [math.NT], 2023-2025. See p. 19, eq. (106).
Ali Shadhar Olaikhan, An Introduction to the Harmonic Series and Logarithmic Integrals, 2nd ed., 2023, section 4.1.14, pp. 273-275.
Cornel Ioan Vălean, More (Almost) Impossible Integrals, Sums, and Series, Springer Cham, 2023. See section 4.19, pp. 419-420, eq.(4.101), section 5.19, pp. 460-461, and section 6.19, pp. 595-601.
FORMULA
Equals 31*zeta(5)/8 - 21*zeta(2)*zeta(3)/16 - 15*log(2)*zeta(4)/8.
EXAMPLE
0.016240657850235703095128372905552235813003886805619...
MATHEMATICA
RealDigits[31*Zeta[5]/8 - 21*Zeta[2]*Zeta[3]/16 - 15*Log[2]*Zeta[4]/8, 10, 120, -1][[1]]
PROG
(PARI) 31*zeta(5)/8 - 21*zeta(2)*zeta(3)/16 - 15*log(2)*zeta(4)/8
CROSSREFS
Sum_{k>=1} H(k) / (2*k+1)^m: A397028 (m=2), A397029 (m=3), this constant (m=4), A397031 (m=5), A397032 (m=6).
Sequence in context: A239578 A248273 A176396 * A198502 A244858 A383081
KEYWORD
nonn,cons
AUTHOR
Amiram Eldar, Jun 14 2026
STATUS
approved