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A395899
Sphenic numbers k = p*q*r, primes p < q < r, such that r < p^3.
1
30, 42, 70, 105, 165, 195, 231, 255, 273, 285, 345, 357, 385, 399, 429, 455, 483, 561, 595, 627, 663, 665, 715, 741, 759, 805, 897, 935, 969, 1001, 1015, 1045, 1085, 1105, 1173, 1235, 1265, 1295, 1309, 1311, 1435, 1463, 1495, 1505, 1547, 1595, 1615, 1645, 1705
OFFSET
1,1
COMMENTS
Proper subset of A393644.
Superset of A383177.
Analogous to A138109, a sequence which instead pertains to squarefree semiprimes A006881.
Let lpf(n) = A020639(n) be the smallest prime factor of n.
Smallest term with lpf(a(n)) = prime(i) is prime(i)*prime(i+1)*prime(i+2) = A046301(n).
Largest term divisible by p = prime(i) is p*q*r, with r = prime(pi(p^3)) and q = r = prime(pi(p^3)-1).
LINKS
Michael De Vlieger, Plot prime(i) | a(n) at (x,y) = (n,i), for n = 1..2400, 8X vertical exaggeration.
EXAMPLE
Let s = A383177 and lpf = A020639.
Table of n, a(n) for select n:
n a(n) lpf(a(n))^3
---------------------------------------------
1 30 = 2 * 3 * 5 8 = 2^3
2 42 = 2 * 3 * 7 8 = 2^3
3 70 = 2 * 5 * 7 8 = 2^3
4 105 = 3 * 5 * 7 27 = 3^3
13 385 = 5 * 7 * 11 125 = 5^3
29 969 = 3 * 17 * 19 27 = 3^3
30 1001 = 7 * 11 * 13 343 = 7^3 = s(1)
39 1309 = 7 * 11 * 17 343 = 7^3 = s(2)
40 1311 = 3 * 19 * 23 27 = 3^3
45 1547 = 7 * 13 * 17 343 = 7^3 = s(3)
68 2431 = 11 * 13 * 17 1331 = 11^3
1980 61585 = 5 * 109 * 113 125 = 5^3
24929 780829 = 7 * 331 * 337 343 = 7^3
.
Let p(m) = prime(m), i the smallest index such that p(m) | a(i), j the smallest index such that lpf(a(j)) = p(m), and k the largest index such that p(m) | a(k). Let c(m) be the number of terms divisible by prime(m).
Table of m, p(m), i, j, k, c(m) for m = 1..5:
m p(m) i j k c(m)
-----------------------------------
1 2 1 1 3 3
2 3 1 4 40 23
3 5 1 13 1980 359
4 7 2 30 24929 2050
5 11 5 68 580381 22461
MAPLE
N:= 2000: # for terms <= N
P:= select(isprime, [2, seq(i, i=3..N/6, 2)]): nP:= nops(P):
sort(select(`<=`, [seq(seq(seq(P[i]*P[j]*P[k], i=1..j-1), j=2..k-1), k = 3..nP)], N)); # Robert Israel, May 11 2026
MATHEMATICA
s = Select[Range[1800], PrimeNu[#] == PrimeOmega[#] == 3 &]; Select[s, Function[{p, q}, AllTrue[q, # < p^3 &]] @@ {First[#1], #2} & @@ TakeDrop[FactorInteger[#][[;; , 1]], 1] &]
KEYWORD
nonn,easy
AUTHOR
Michael De Vlieger, May 09 2026
STATUS
approved