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A395472
Decimal expansion of the angle theta (in radians) such that 5*theta and 3*theta are the half central angles of the circular arcs of a constructible squarable lune.
7
2, 9, 3, 1, 0, 9, 1, 9, 7, 3, 0, 1, 4, 0, 4, 3, 5, 8, 2, 3, 2, 8, 9, 3, 0, 9, 9, 1, 5, 5, 0, 9, 8, 8, 3, 9, 2, 8, 1, 0, 4, 5, 1, 6, 0, 2, 7, 0, 6, 7, 5, 4, 6, 9, 0, 8, 1, 7, 5, 8, 0, 0, 0, 5, 0, 2, 8, 8, 2, 4, 5, 6, 6, 6, 2, 9, 7, 2, 9, 5, 7, 7, 8, 7, 1, 9, 1, 7, 0, 5, 2, 4, 2, 9, 9, 4, 3, 9, 2, 3, 3, 9, 7, 3, 5
OFFSET
0,1
COMMENTS
The angle in degrees is 16.793... . The two half central angles are 5*theta = 1.465... = 83.969... degrees, and 3*theta = 0.879... = 50.381... degrees.
See A395465 for details, references and more links.
LINKS
Amiram Eldar, Illustration.
Mikhail Mikhailovich Postnikov, The Problem of Squarable Lunes, The American Mathematical Monthly, Vol. 107, No. 7 (2000), pp. 645-651. Translated from Russian by Abe Shenitzer.
FORMULA
Equals arccos((sqrt(5/3) - 1 + sqrt(20/3 + sqrt(20/3)))/4)/2.
EXAMPLE
0.293109197301404358232893099155098839281045160270675...
MATHEMATICA
RealDigits[ArcCos[(Sqrt[5/3] - 1 + Sqrt[20/3 + Sqrt[20/3]])/4]/2, 10, 120][[1]]
PROG
(PARI) acos((sqrt(5/3) - 1 + sqrt(20/3 + sqrt(20/3)))/4)/2
KEYWORD
nonn,cons
AUTHOR
Amiram Eldar, Apr 24 2026
STATUS
approved