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A395407
Decimal expansion of Sum_{k>=1} H(k)/(k+1)!, where H(k) = A001008(k)/A002805(k) is the k-th harmonic number.
0
8, 4, 7, 4, 8, 0, 0, 6, 3, 8, 7, 2, 5, 3, 2, 4, 6, 4, 5, 6, 0, 9, 7, 7, 5, 0, 4, 2, 4, 3, 1, 9, 8, 7, 3, 0, 4, 0, 6, 5, 1, 9, 5, 2, 1, 9, 4, 8, 6, 5, 9, 6, 9, 7, 3, 8, 9, 6, 7, 7, 9, 7, 4, 8, 9, 7, 2, 9, 6, 3, 1, 8, 0, 4, 1, 6, 5, 9, 2, 3, 5, 3, 6, 4, 9, 7, 2, 3, 8, 8, 3, 0, 7, 1, 6, 4, 5, 4, 9, 8, 1, 0, 4, 6, 7
OFFSET
0,1
LINKS
J. Hammond, Problem 6609, Mathematical Questions with Their Solutions: From the "Educational Times", Vol. 60 (1894), p. viii; Solution by H. J. Woodall, ibid., pp. 81-82.
Leroy Quet, Problem 10398, The American Mathematical Monthly, Vol. 101, No. 7 (1994), p. 682; The Effect of an Alternating Series, Solution to Problem 10398 by Michael Vowe, ibid., Vol. 104, No. 5 (1997), p. 462.
Michael I. Shamos, A catalog of the real numbers, 2007, p. 602.
FORMULA
Equals e * Sum_{k>=1} H(k)*(-1)^(k+1)/(k+1)! (Quet, 1994).
Equals gamma - Ei(1) + Sum_{k>=1} H(k) / k! = A001620 - A091725 + A347952.
Equals Integral_{x=0..1} exp(x)*log(x/(1-x)) dx (Hammond, 1894).
Formulas from Shamos (2007):
Equals gamma * (1 + e) - Ei(1) - e*Ei(-1) = A001620 * (1 + A001113) - A091725 - A001113*(-A099285).
Equals Sum_{k>=2} (gamma - psi(k))/k!, where psi is the digamma function.
Equals Sum_{k>=1} Sun_{m=1..k} 1/(m*(k+1)!) = e * Sum_{k>=1} Sun_{m=1..k} (-1)^(k+1)/(m*(k+1)!).
EXAMPLE
0.847480063872532464560977504243198730406519521948659...
MATHEMATICA
RealDigits[EulerGamma * (1 + E) - ExpIntegralEi[1] - E * ExpIntegralEi[-1], 10, 120][[1]]
PROG
(PARI) Euler * (1 + exp(1)) - real(-eint1(-1)) + exp(1) * eint1(1)
KEYWORD
nonn,cons
AUTHOR
Amiram Eldar, Apr 21 2026
STATUS
approved