OFFSET
1,4
COMMENTS
All terms are odd.
Numerical evidence suggests that a(n) ~ n/2.
The sequence does not terminate for all n <= 3*10^10 (verified computationally).
The differences a(n+1)-a(n) exhibit a dyadic, self-similar pattern on a logarithmic scale.
LINKS
Marco Mantovanelli, Table of n, a(n) for n = 1..2000
Benoit Cloitre, On a perturbed Hofstadter Q-recursion, arXiv:2604.06237 [math.NT], 2026.
Marco Mantovanelli, Dyadic Self-Similarity in a Perturbed Hofstadter Q-Recursion, arXiv:2603.16111 [math.CO], 2026.
Marco Mantovanelli, Preprint: Dyadic Self-Similarity in a Perturbed Hofstadter Q-Recursion.
Marco Mantovanelli, Certified Finite-State Induction for a Perturbed Hofstadter Recursion, arXiv:2603.29622 [math.CO], 2026. See p. 3.
FORMULA
a(1)=a(2)=1; for n > 2: a(n) = a(n-a(n-1)) + a(n-a(n-2)) + (-1)^n.
a(n)/n = 1/2 + O(1/sqrt(log(n))). - Benoit Cloitre, Apr 03 2026
More precisely it can be proved that limsup_{n->oo} sqrt(log_2(n)) * |a(n)/n - 1/2| = 1/(3*sqrt(2*Pi)). - Benoit Cloitre, Apr 08 2026
MATHEMATICA
Q[1] = 1; Q[2] = 1;
Q[n_Integer?Positive] := Q[n] = Q[n - Q[n - 1]] + Q[n - Q[n - 2]] + (-1)^n;
Table[Q[n], {n, 1, 350}]
CROSSREFS
KEYWORD
nonn,look
AUTHOR
Marco Mantovanelli, Mar 08 2026
STATUS
approved
