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A393119
Decimal expansion of Sum_{k>=1} (-1)^(k+1) * (AH(k)/k)^2, where AH(K) = A058313(k)/A058312(k) is the k-th alternating harmonic (or skew-harmonic) number.
6
1, 0, 2, 0, 7, 6, 2, 6, 1, 3, 1, 0, 1, 2, 6, 7, 3, 0, 4, 8, 9, 2, 1, 0, 3, 9, 3, 9, 0, 9, 5, 9, 0, 3, 0, 0, 5, 3, 0, 3, 6, 6, 5, 6, 6, 5, 0, 2, 5, 0, 6, 1, 6, 5, 8, 8, 2, 7, 5, 6, 0, 9, 0, 7, 7, 8, 5, 2, 1, 4, 2, 5, 1, 4, 8, 4, 9, 2, 9, 8, 9, 7, 9, 0, 2, 3, 4, 7, 5, 1, 3, 9, 2, 6, 7, 7, 3, 5, 6, 4, 6, 1, 1, 3, 9
OFFSET
1,3
LINKS
Ce Xu, Yingyue Yang, and Jianwen Zhang, Explicit evaluation of quadratic Euler sums, International Journal of Number Theory, Vol. 13, No. 3 (2017), pp. 655-672; arXiv preprint, arXiv:1609.04923 [math.NT], 2016. See Example 3.6.
FORMULA
Equals (1/6)*log(2)^4 + 2*log(2)^2*zeta(2) + (7/4)*log(2)*zeta(3) - (61/16)*zeta(4) + 4*Li_4(1/2), where Li_4(z) is the polylogarithm function of order 4.
EXAMPLE
1.020762613101267304892103939095903005303665665025061...
MATHEMATICA
RealDigits[(1/6)*Log[2]^4 + 2*Log[2]^2*Zeta[2] + (7/4)*Log[2]*Zeta[3] - (61/16)*Zeta[4] + 4*PolyLog[4, 1/2], 10, 120][[1]]
PROG
(PARI) (1/6)*log(2)^4 + 2*log(2)^2*zeta(2) + (7/4)*log(2)*zeta(3) - (61/16)*zeta(4) + 4*polylog(4, 1/2)
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
Amiram Eldar, Feb 02 2026
STATUS
approved