OFFSET
3,1
COMMENTS
The total surface area of five-element sets of cuboids is given by the sum of surface area 2*(x*y + y*z + z*x) of each cuboid x X y X z in the set.
LINKS
FORMULA
Conjecture: a(n) = 2*(A054567(n+1) + 1).
EXAMPLE
According to A384479(4) there are 31 sets of cuboids in total that fill 4 X 4 X 4 cube, and only one set produces the minimum total surface area, {(1 X 1 X 1), (1 X 1 X 2), (1 X 1 X 4), (1 X 3 X 3), (3 X 4 X 4)} with total area 145. Therefore a(4) = 144 since the minimum total area of five cuboids is 144.
CROSSREFS
KEYWORD
nonn,more
AUTHOR
Janaka Rodrigo, Feb 01 2026
EXTENSIONS
a(18)-a(24) from Sean A. Irvine, Feb 06 2026
STATUS
approved
