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A390986
Integers k such that all prime factors of k^2+1 are Sophie Germain primes.
1
1, 2, 3, 7, 9, 12, 15, 17, 23, 32, 39, 40, 41, 45, 53, 77, 93, 110, 128, 144, 155, 160, 170, 171, 182, 198, 218, 219, 247, 250, 258, 301, 309, 318, 321, 322, 331, 332, 345, 347, 357, 373, 375, 383, 419, 426, 427, 440, 441, 442, 452, 479, 482, 490, 492, 500, 510
OFFSET
1,2
COMMENTS
The sequence contains A389884.
LINKS
EXAMPLE
17 is a term because the prime factors of 17^2+1 = 290 are 2, 5 and 29 with 2 = A005384(1), 5 = A005384(3) and 29 = A005384(6).
MAPLE
with(numtheory):nn:=510:
for k from 1 to nn do:
it:=0:d:=factorset(k^2+1):n0:=nops(d):
for j from 1 to n0 do:
if isprime(2*d[j]+1) then it:=it+1:else fi:od:
if it=n0 then printf(`%d, `, k) else fi:od:
# Alternative:
q:= n-> andmap(p-> isprime(2*p+1), ifactors(n^2+1)[2][.., 1]):
select(q, [$1..510])[]; # Alois P. Heinz, Nov 25 2025
MATHEMATICA
q[k_] := AllTrue[FactorInteger[k^2 + 1][[;; , 1]], PrimeQ[2*# + 1] &]; Select[Range[512], q] (* Amiram Eldar, Nov 25 2025 *)
PROG
(PARI) isok(k) = my(f=factor(k^2+1)[, 1]); #select(x->isprime(2*x+1), f) == #f; \\ Michel Marcus, Nov 25 2025
CROSSREFS
KEYWORD
nonn
AUTHOR
Michel Lagneau, Nov 25 2025
STATUS
approved