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A390043
Composite numbers k such that binomial(4*k, k) == 4^k (mod k).
0
4, 6, 18, 30, 39, 54, 56, 68, 84, 92, 184, 208, 992, 2704, 16256, 27424, 52064, 129848, 225229, 514688, 616688, 1194649, 1818176, 3788416, 12327121, 53703248, 67100672, 2160093568, 2779417328, 3899921104
OFFSET
1,1
COMMENTS
If k is prime, then binomial(4*k, k) == 4^k (mod k).
If p is a prime such that p^2 divides 4^(p-1) - 1, then p^2 is a term.
PROG
(Python)
from itertools import count, islice
from sympy import isprime
from oeis_sequences.OEISsequences import binom_mod
def A390043_gen(startvalue=4): # generator of terms >= startvalue
for j in count(max(startvalue, 4)):
if not isprime(j) and binom_mod(j<<2, j, j) == pow(4, j, j):
yield j
A390043_list = list(islice(A390043_gen(), 20))
(PARI) isok(k) = !isprime(k) && binomod(4*k, k, k)==Mod(4, k)^k; \\ Michel Marcus, Jan 16 2026; using binomod.gp by M. Alekseyev
CROSSREFS
KEYWORD
nonn,hard,more
AUTHOR
Chai Wah Wu, Jan 15 2026
EXTENSIONS
a(29)-a(30) from Chai Wah Wu, Jan 19 2026
STATUS
approved