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A388973
The number of exponential divisors of the numbers whose number of exponential divisors is a power of 2.
5
1, 1, 1, 2, 1, 1, 1, 2, 2, 1, 1, 2, 1, 1, 1, 1, 2, 1, 2, 1, 1, 1, 2, 2, 1, 2, 2, 1, 1, 1, 2, 1, 1, 1, 4, 1, 1, 1, 2, 1, 1, 1, 2, 2, 1, 1, 2, 2, 1, 2, 1, 2, 1, 2, 1, 1, 1, 2, 1, 1, 2, 4, 1, 1, 1, 2, 1, 1, 1, 4, 1, 1, 2, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 2, 1, 2, 1, 2
OFFSET
1,4
LINKS
FORMULA
a(n) = A049419(A388972(n)).
a(n) = 2^A388974(n).
Asymptotic mean: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = (1/d) * Product_{p prime} ((1 - 1/p) * (1 + Sum_{k>=1} A000005(A036537(k))/p^k)) = 1.50562990102073270647..., where d = 0.957956... is the asymptotic density of A388972 (see the Formula section of A388972).
MATHEMATICA
f[p_, e_] := DivisorSigma[0, e]; d[1] = 1;
d[n_] := Times @@ f @@@ FactorInteger[n];
pow2Q[n_] := n == 2^IntegerExponent[n, 2];
q[n_] := pow2Q[d[n]]; d /@ Select[Range[100], q]
PROG
(PARI) d(n) = vecprod(apply(numdiv, factor(n)[, 2])); \\ A049419
ispow2(n) = n >> valuation(n, 2) == 1;
list(kmax) = {my(d1); for(k = 1, kmax, d1 = d(k); if(ispow2(d1), print1(d1, ", "))); }
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Amiram Eldar, Sep 22 2025
STATUS
approved