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A388301
a(n) is the number of steps to reach n again when the Sisyphus sequence (A350877) begins with n, or -1 if n is never reached.
1
7, 7, 7, 7, 3, 7, 25, 7, 1937682, 3, 23, 20, 16, 25, 18, 19, 161, 1937682, 149, 13, 30, 23, 26, 20, 50, 16, 30, 25, 43, 18, 26, 741, 55, 161, 839, 1937682, 68, 149, 39, 44, 1630, 30, 42, 481, 527813878, 26, 125, 49, 640, 50, 96, 32, 21120, 30, 129, 114, 107, 43, 124, 35
OFFSET
1,1
COMMENTS
a(127) > 5261947751483 and a(211) > 1261930000000.
EXAMPLE
a(10) = 3 because 3 steps are needed to end up again at 10:
Step 1: 10 is even and 10/2 = 5;
Step 2: 5 is odd and 5 + 2 (= first prime) = 7;
Step 3: 7 is odd and 7 + 3 (= second prime) = 10.
PROG
(Python)
from itertools import count
from sympy import nextprime
A388301 = []
for n in range(1, 45):
m, prime = n, 0
for steps in count(1):
if m % 2: m += (prime:=nextprime(prime))
else: m //= 2
if m == n: break
A388301.append(steps)
print(A388301)
CROSSREFS
Sequence in context: A103983 A232127 A388255 * A195413 A083947 A269349
KEYWORD
nonn
AUTHOR
Karl-Heinz Hofmann, Sep 16 2025
STATUS
approved