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A386606
Numbers with exactly 3 distinct odd prime factors.
2
105, 165, 195, 210, 231, 255, 273, 285, 315, 330, 345, 357, 385, 390, 399, 420, 429, 435, 455, 462, 465, 483, 495, 510, 525, 546, 555, 561, 570, 585, 595, 609, 615, 627, 630, 645, 651, 660, 663, 665, 690, 693, 705, 714, 715, 735, 741, 759, 765, 770, 777, 780
OFFSET
1,1
COMMENTS
The cyclotomic polynomials Phi_a(n) (see A013595 and A013596, which are the same for n >= 4) of these numbers may contain coefficients as given in the irregular triangle A013595(a(n),m) (or A013596(a(n),m)), which are equal to 2 or -2. It seems that most of these numbers satisfy this condition. Counterexamples begin a(5) = 231, a(15) = 399, a(18) = 435 (see also A391069).
Some of the cyclotomic polynomials of these numbers contain coefficients which are in {-3, 3}; for example for a(n) = 1309, 1330 and 1463 with n = 119, 123 and 139 respectively, or even coefficients in {-4, 4} as for example for a(297) = 2431, or in {-5, 5} as in a(353) = 2717.
LINKS
FORMULA
Equals Union_{k >= 0} 2^k*A278569; i.e., A278569 is the subsequence of all odd terms in this sequence.
EXAMPLE
390 is a term since 390 = 2 * 3 * 5 * 13 has exactly 3 odd prime factors (3,5,13).
525 is a term since 525 = 3 * 5^2 * 7 has exactly 3 odd prime factors (3,5,7).
MAPLE
filter:= proc(n) local L;
L:= ifactors(n)[2];
nops(select(t -> t[1] <> 2, L)) = 3
end proc:
select(filter, [$1..1000]); # Robert Israel, Dec 01 2025
MATHEMATICA
Select[Range[800], PrimeNu[# / 2^IntegerExponent[#, 2]] == 3 &] (* Amiram Eldar, Nov 21 2025 *)
PROG
(PARI) is(k) = (omega(k >> valuation(k, 2))==3); \\ Jason Yuen, Dec 24 2025
CROSSREFS
KEYWORD
nonn
AUTHOR
A.H.M. Smeets, Nov 21 2025
STATUS
approved