login
A385375
Numbers k that can't be partitioned into tau(k) distinct parts.
2
2, 4, 6, 8, 12, 18, 20, 24, 30, 36, 48, 60, 72, 120
OFFSET
1,1
COMMENTS
Numbers k for which k < A000217(tau(k)).
To partition k into tau(k) distinct parts, k >= tau(k)*(tau(k) + 1)/2. According to A374793, k > tau(k)^2 > tau(k)*(tau(k) + 1)/2 for k > 1260. The sequence is therefore finite and contains 14 terms.
EXAMPLE
6 is a term because there is no partition of 6 into tau(6) = 4 distinct parts.
MAPLE
with(NumberTheory):
A385375:=proc(K)
local k, l;
l:=[];
for k from 1 to K do
if tau(k)*(tau(k)+1)/2>k then
l:=[op(l), k];
end if;
end do;
return op(l);
end proc:
A385375(1260);
MATHEMATICA
s={}; Do[t=DivisorSigma[0, k]; If[NoneTrue[Length/@Union/@IntegerPartitions[k, {t}], #==t&], AppendTo[s, k]], {k, 72}]; s (* James C. McMahon, Jul 24 2025 *)
CROSSREFS
KEYWORD
nonn,fini,full
AUTHOR
Felix Huber, Jul 11 2025
STATUS
approved