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A384686
a(n) = 2^(n-4)*(5*binomial(n,5) + 6*binomial(n,4)).
2
0, 0, 0, 0, 6, 70, 480, 2520, 11200, 44352, 161280, 549120, 1774080, 5491200, 16400384, 47523840, 134184960, 370442240, 1002700800, 2667184128, 6985482240, 18042716160, 46022000640, 116064256000, 289696382976, 716282265600, 1755735654400, 4269382041600, 10305404928000
OFFSET
0,5
COMMENTS
a(n) is the number of words of length n defined on 5 letters that have exactly two a's and exactly two b's and no c's or exactly two a's and exactly three c's and no b's.
FORMULA
a(n) = (1/3)*2^(n-7)*(n-3)*(n-2)*(n-1)*n*(n+2).
E.g.f.: (x^2/2)*exp(2*x)*(x^2/2 + x^3/6).
G.f.: 2*x^4*(3 - x)/(1 - 2*x)^6. - Stefano Spezia, Jun 07 2025
From Amiram Eldar, Sep 29 2025: (Start)
Sum_{n>=4} 1/a(n) = 12*log(2)/5 - 37/25.
Sum_{n>=4} (-1)^n/a(n) = 324*log(3/2)/5 - 653/25. (End)
EXAMPLE
a(4) = 6 since the words are the 6 permutations of aabb.
a(6) = 480 since the words are the 90 permutations of aabbdd, the 180 permutations of aabbde, the 90 permutations of aabbee, the 60 permutations of aacccd, and the 60 permutations of aaccce.
MATHEMATICA
A384686[n_] := 2^(n - 4)*(5*Binomial[n, 5] + 6*Binomial[n, 4]);
Array[A384686, 30, 0] (* Paolo Xausa, Jun 13 2025 *)
LinearRecurrence[{12, -60, 160, -240, 192, -64}, {0, 0, 0, 0, 6, 70}, 40] (* Harvey P. Dale, Jul 19 2025 *)
CROSSREFS
Cf. A384506.
Sequence in context: A188406 A048708 A286527 * A104900 A186667 A001448
KEYWORD
nonn,easy
AUTHOR
Enrique Navarrete, Jun 07 2025
STATUS
approved