OFFSET
1,1
COMMENTS
a(n) <= 945 for all n. a(n) = 945 for prime numbers > 103.
The possible values appear to be: 1, 3, 5, 7, 9, 15, 21, 25, 27, 35, 45, 63, 105, 135, 189, 315, 945. - Michel Marcus, Jun 12 2025
LINKS
Robert Israel, Table of n, a(n) for n = 1..10000
EXAMPLE
a(5) = 189 because 189 is the smallest odd multiplier k such that 5*k is abundant (i.e., 5*189 = 945 which is abundant).
MAPLE
f:= proc(n) local k;
for k from 1 by 2 do if numtheory:-sigma(n*k) > 2*n*k then return k fi od
end proc:
map(f, [$1..100]); # Robert Israel, Jun 09 2025
MATHEMATICA
a[n_] := Module[{k = 1}, While[DivisorSigma[-1, k*n] <= 2, k += 2]; k]; Array[a, 100] (* Amiram Eldar, Jun 06 2025 *)
PROG
(PARI) a(n) = my(k=1); while (sigma(k*n, -1)<=2, k+=2); k; \\ Michel Marcus, Jun 09 2025
CROSSREFS
KEYWORD
nonn
AUTHOR
Sergio Pimentel, Jun 06 2025
STATUS
approved
