A384662 Solution of the complementary equation b(n)=a(a(n))+a(n)+2 with a(1)=1; this is the sequence b.

4, 6, 8, 14, 19, 23, 25, 28, 30, 32, 37, 39, 41, 44, 49, 52, 55, 60, 64, 67, 73, 78, 82, 84, 87, 89, 94, 99, 103, 106, 110, 113, 115, 118, 122, 124, 129, 131, 135, 138, 140, 142, 148, 150, 153, 158, 160, 165, 167, 169, 171, 174, 178, 181, 183, 186, 190, 193

Offset

1,1

Comments

Sequence a is A384661.

Links

Table of n, a(n) for n=1..58.

Clark Kimberling, Complementary equations, J. Int. Seq. Article 07.1.4 (2007), 1-13.

Formula

{b(n)-b(n-1) : n>=2} = {2, 3, 4, 5, 6}.

Example

b(1) = a(a(1))+a(1)+2 = 1+1+2 = 4;
b(2) = a(a(2))+a(2)+2 = 2+2+2 = 6;
b(3) = a(a(3))+a(3)+2 = 3+3+2 = 8;
b(4) = a(a(4))+a(4)+2 = 5+7+2 = 14.

Crossrefs

Cf. A136498, A136499, A136500, A384661, A384663, A384664.

Sequence in context: A200077 A256137 A116897 * A293763 A389920 A246324

Adjacent sequences: A384659 A384660 A384661 * A384663 A384664 A384665

Keyword

nonn

Author

Clark Kimberling, Jun 09 2025

Status

approved