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A382954
Number of ways to partition distinct prime numbers into three disjoint sets such that the sum of each set equals n.
1
1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 2, 0, 1, 0, 1, 3, 2, 8, 1, 1, 4, 0, 14, 9, 1, 4, 7, 16, 26, 31, 17, 3, 19, 39, 54, 20, 62, 9, 41, 96, 89, 62, 66, 34, 59, 197, 241, 289, 69, 124, 184, 133, 481, 440, 148, 225, 394, 709, 808, 984, 555, 414, 799
OFFSET
0,25
COMMENTS
Conjecture: a(n) > 0 for n > 35.
FORMULA
a(n) = 1/6 * [(x*y*z)^n] Product_{p prime} (1 + x^p + y^p + z^p) for n > 0.
EXAMPLE
a(29) = 3: [29; 19, 7, 3; 13, 11, 5], [29; 17, 7, 3, 2; 13, 11, 5], [29; 17, 7, 5; 13, 11, 3, 2].
a(30) = 2: [23, 7; 19, 11; 17, 13], [23, 5, 2; 19, 11; 17, 13].
CROSSREFS
KEYWORD
nonn
AUTHOR
Seiichi Manyama, Apr 10 2025
STATUS
approved