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A382906
The powerful part of the n-th biquadratefree number.
5
1, 1, 1, 4, 1, 1, 1, 8, 9, 1, 1, 4, 1, 1, 1, 1, 9, 1, 4, 1, 1, 1, 8, 25, 1, 27, 4, 1, 1, 1, 1, 1, 1, 36, 1, 1, 1, 8, 1, 1, 1, 4, 9, 1, 1, 49, 25, 1, 4, 1, 27, 1, 8, 1, 1, 1, 4, 1, 1, 9, 1, 1, 1, 4, 1, 1, 1, 72, 1, 1, 25, 4, 1, 1, 1, 1, 1, 4, 1, 1, 1, 8, 1, 9, 1
OFFSET
1,4
FORMULA
a(n) = A057521(A046100(n)).
a(n) = A046100(n)/A382905(n).
Sum_{k=1..n} a(k) ~ c * n^(3/2) / 3, where c = zeta(4)^(3/2) * Product_{p prime} (1 + 2/p^(3/2) - 1/p^2 - 2/p^(5/2)) = 2.21177275344948791706... .
MATHEMATICA
f[p_, e_] := p^If[e > 1, e, 0]; s[n_] := Module[{fct = FactorInteger[n]}, If[AllTrue[fct[[;; , 2]], # < 4 &], Times @@ f @@@ fct, Nothing]]; Array[s, 100]
PROG
(PARI) list(lim) = {my(f); print1(1, ", "); for(k = 2, lim, f = factor(k); if(vecmax(f[, 2]) < 4, print1(prod(i = 1, #f~, f[i, 1]^if(f[i, 2] > 1, f[i, 2], 0)), ", "))); }
CROSSREFS
Similar sequences: A382902, A382903, A382904, A382905.
Sequence in context: A088440 A300253 A212173 * A366993 A274006 A203025
KEYWORD
nonn,easy
AUTHOR
Amiram Eldar, Apr 08 2025
STATUS
approved