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A379420
a(n) = n + [n*s/r] + [n*t/r], where r = 5^(1/4); s = 5^(1/2); t = 5^(3/4) and [ ] = floor.
3
4, 8, 13, 17, 23, 27, 32, 36, 42, 46, 51, 55, 61, 65, 70, 74, 80, 84, 89, 93, 98, 103, 108, 112, 117, 122, 127, 131, 136, 141, 146, 150, 155, 160, 165, 169, 174, 178, 184, 188, 193, 197, 203, 207, 212, 216, 222, 226, 231, 235, 241, 245, 250, 254, 259, 264
OFFSET
1,1
COMMENTS
This sequence and A379421 and A379422 partition the positive integers; see A184812 for a proof.
For each k in A000027, write "a" if k=A379420(n) for some n, "b" if k=A379421(n) for some n, and "c" if k=A379422(n) for some n. Concatenating these letters for k = 1,2,3,... spells the following infinite word:
cbcabccabcbcacbcabccbcabccabcbcacbcabccbcabccabcbcacbcabccbcabccabcbcacbcabccbcabccabcbcacbcabccbacbccabcbcacbcabccbacbccabcbca...
FORMULA
a(n) = n + [n*s/r] + [n*t/r], where r = 5^(1/4); s = 5^(1/2); t = 5^(3/4) and [ ] = floor.
a(n) = n + [n*r] + [n*r^2], where r = 5^(1/4) and [ ] = floor.
MATHEMATICA
r = 5^(1/4); s = 5^(1/2); t = 5^(3/4);
Table[n + Floor[n*s/r] + Floor[n*t/r], {n, 1, 120}] (* A379420 *)
Table[n + Floor[n*r/s] + Floor[n*t/s], {n, 1, 120}] (* A379421 *)
Table[n + Floor[n*r/t] + Floor[n*s/t], {n, 1, 120}] (* A379422 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Clark Kimberling, Jan 20 2025
STATUS
approved