OFFSET
1,16
COMMENTS
The intersection of the normalizers of all subgroups of G is also called the Baer norm.
N(G) = Z(G) for every group of cubefree order. (See the Miles Englezou link for a proof.)
REFERENCES
R. Baer, Norm and hypernorm, Publ. Math. Debrecen, 4 (1956), 347-350.
LINKS
Wikipedia, Norm (group)
Miles Englezou, Proof that N(G) = Z(G) for groups of cubefree order
FORMULA
|N(G)| >= |Z(G)|. If n is a term of A051532 then a(n) = 0, since G = Z(G) = N(G).
By Baer (1956), Z(G) = 1 implies N(G) = 1. Hence no centerless group G satisfies |N(G)| <> |Z(G)|.
EXAMPLE
a(3) = 0 since Z(C3) = N(C3) = C3, and C3 is the only group of order 3.
a(8) = 1 since |Z(Q8)| = 2 and |N(Q8)| = 8, and for other groups G of order 8 we get |N(G)| = |Z(G)|.
PROG
(GAP)
U:=[];; LoadPackage("sonata");;
for n in [1..64] do
T:=[];;
for i in [1..NrSmallGroups(n)] do
S:=[];;
G:=SmallGroup(n, i);;
for k in [1..Length(Subgroups(G))] do
S:=Concatenation(S, [Normaliser(G, Subgroups(G)[k])]);
od;
if Size(Intersection(S))<>Order(Centre(G)) then
T:=Concatenation(T, [i]);
fi;
od;
U:=Concatenation(U, [Size(T)]);
od;
Print(U);
CROSSREFS
KEYWORD
nonn
AUTHOR
Miles Englezou, Aug 11 2024
STATUS
approved