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A375079
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a(n) = a(n-1) + a(n-2) + ... + a(n-k) where k = (a(n-1) mod (n-1)) + 1 for n >= 3, with a(1) = 1 and a(2) = 2.
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0
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1, 2, 2, 5, 7, 14, 26, 56, 56, 138, 306, 612, 612, 1224, 3004, 5758, 11822, 23476, 45284, 91792, 184140, 368224, 735948, 1472492, 2944996, 5889992, 11411652, 23191624, 46290860, 92672900, 185346856, 370693871, 741375929, 1479818680, 2962582344, 5925164688
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OFFSET
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1,2
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COMMENTS
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It appears that the ratio a(n+1)/a(n) -> 2.
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LINKS
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FORMULA
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a(n) = Sum_{i=1 .. (a(n-1) mod (n-1)) + 1} a(n-i).
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EXAMPLE
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For n = 7, we add up the previous a(7-1) mod (7-1) + 1 = 3 terms to get a(7) = a(6) + a(5) + a(4) = 14 + 7 + 5 = 26.
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MATHEMATICA
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Modanacci={1, 2}; Do[AppendTo[Modanacci, Sum[Modanacci[[-i]], {i, Mod[Modanacci[[-1]], Length[Modanacci]]+1}]], 100]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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