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A374152
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Number of divisors d of n such that d^(n/d) == d (mod (d + n/d)).
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0
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1, 2, 2, 2, 2, 2, 2, 3, 3, 2, 2, 2, 2, 3, 4, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 2, 2, 4, 2, 3, 2, 2, 4, 3, 2, 3, 3, 4, 2, 2, 2, 3, 2, 2, 2, 3, 3, 3, 3, 3, 2, 3, 3, 2, 2, 2, 2, 2, 2, 3, 6, 3, 3, 2, 2, 2, 2, 2, 2, 3, 2, 3, 5, 2, 3, 2, 2, 3, 3, 2, 2, 4, 2, 2, 2, 3, 2, 5
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OFFSET
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1,2
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COMMENTS
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For all n, the divisors counted in a(n) include 1 and n.
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LINKS
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EXAMPLE
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a(8) = 3 because the divisors of 8 are 1, 2, 4 and 8, and
1^(8/1) == 1 (mod (1 + 8/1)),
4^(8/4) == 4 (mod (4 + 8/4)) and
8^(8/8) == 8 (mod (8 + 8/8)), but
2^(8/2) != 2 (mod (2 + 8/2)).
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MATHEMATICA
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a[n_]:=Sum[Boole[Mod[d^(n/d), n/d+d]==d], {d, Divisors[n]}]; Array[a, 90] (* Stefano Spezia, Jun 30 2024 *)
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PROG
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(Magma) [#[d: d in Divisors(n) | d^(n div d) mod ((n div d)+d) eq d]: n in [1..90]]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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