A372450 a(n) = k, if A086893(k) is the first term of A086893 reached on the trajectory of reduced Collatz-function R, when starting from 2n-1, or -1 if no term of A086893 is ever encountered.

1, 2, 3, 4, 4, 4, 4, 6, 4, 4, 5, 6, 4, 6, 4, 6, 4, 6, 4, 4, 6, 4, 4, 6, 4, 4, 6, 6, 4, 4, 6, 6, 4, 4, 4, 6, 6, 7, 4, 4, 6, 6, 7, 4, 4, 6, 6, 6, 6, 4, 4, 6, 4, 6, 6, 6, 7, 4, 4, 4, 6, 4, 6, 4, 6, 4, 4, 4, 6, 4, 6, 6, 6, 6, 4, 9, 4, 6, 4, 6, 6, 6, 6, 6, 4, 6, 4, 6, 4, 4, 4, 6, 4, 4, 6, 4, 6, 6, 4, 6, 9, 4, 4, 6, 4, 4, 8, 6

Offset

1,2

Comments

The length of the binary expansion of the first term of A086893 that comes along when starting from x = 2*n-1 and then repeating the operation x -> A000265(3*x+1). If 2n-1 itself is in A086893, then its binary length is used.

Terms A016789(n) = 2, 5, 8, 11, 14, 17, ... occur only once in this sequence because A086893(A016789(n)) are all multiples of 3: 3, 21, 213, 1365, 13653, 87381, 873813, 5592405, 55924053, 357913941, ..., while the terms of A075677 never are. Note that all terms > 1 of A086893 are just one or two invocations of R away from 1.

Links

Antti Karttunen, Table of n, a(n) for n = 1..100000

Index entries for sequences related to 3x+1 (or Collatz) problem

Example

a(11) = 5 because the first term of A086893 that occurs on the trajectory of 21 (= 2*11-1) is 21 = A086893(5).
a(14) = 6 because the first term of A086893 that occurs on the trajectory of 27 (= 2*14-1) is A372443(39) = 53 = A086893(6).

Prog

(PARI)
A000265(n) = (n>>valuation(n, 2));
A000523(n) = logint(n, 2);
A086893(n) = (if(n%2, 2^(n+1), 2^(n+1)+2^(n-1))\3);
A372358(n) = bitxor(n, A086893(1+A000523(n)));
A372450(n) = { n=2*n-1; while(A372358(n)>0, n=A000265(3*n+1)); (1+A000523(n)); };

Crossrefs

Cf. A000265, A000523, A016789, A075677, A086893, A372358, A372443.

Sequence in context: A029106 A064004 A195849 * A087827 A136528 A263252

Adjacent sequences: A372447 A372448 A372449 * A372451 A372452 A372453

Keyword

nonn

Author

Antti Karttunen, May 03 2024

Status

approved