|
|
A370250
|
|
Numbers k such that the sum of the digits times the square of the sum of the fourth powers of the digits equals k.
|
|
0
|
|
|
|
OFFSET
|
1,3
|
|
COMMENTS
|
There are exactly 5 such numbers (Property 17 of Clerc).
|
|
LINKS
|
|
|
EXAMPLE
|
7253758561 = (7+2+5+3+7+5+8+5+6+1)*(7^4 + 2^4 + 5^4 + 3^4 + 7^4 + 5^4 + 8^4 + 5^4 + 6^4 + 1^4)^2 = 49*148035889 = 7253758561.
|
|
PROG
|
(PARI) niven142(k) = my(d=digits(k)); vecsum(d)*sum(i=1, #d, d[i]^4)^2 == k;
for(k=0, 10^12, if(niven142(k)==1, print1(k, ", ")))
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,base,fini,full
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|