login
A367350
Analog of A121805, but starting with 6.
9
6, 73, 104, 145, 196, 258, 341, 354, 397, 471, 485, 540, 545, 601, 617, 693, 730, 737, 815, 873, 912, 941, 960, 969, 1060, 1061, 1072, 1093, 1124, 1165, 1216, 1277, 1348, 1429, 1520, 1521, 1532, 1553, 1584, 1625, 1676, 1737, 1808, 1889, 1980, 1981, 1992, 2014, 2056, 2118
OFFSET
1,1
COMMENTS
Contains 209534289952018960 terms, the last term being a(209534289952018960) = 9999999999999999936.
LINKS
MATHEMATICA
b = 10; m = b - 1; a[1] = 6; a[n_] := a[n] = For[r = Mod[a[n - 1], b]; y = 0, y <= m, y++, If[y == IntegerDigits[#, b][[1]], Return[#]] &[a[n - 1] + b r + y]]; Array[a, 45] (* Michael De Vlieger, Nov 18 2023, after Jean-François Alcover at A121805 *)
PROG
(Python)
from itertools import count, islice
def agen(start=6): # generator of terms
an, y = start, 1
while y < 10:
yield an
an, y = an + 10*(an%10), 1
while y < 10:
if str(an+y)[0] == str(y):
an += y
break
y += 1
print(list(islice(agen(), 50))) # Michael S. Branicky, Nov 18 2023
CROSSREFS
Comma sequences in base 10, starting with 1, 2, 4, 5, 6, 7, 8, 9, 10 are A121805, A139284, A366492, A367337, A367350, A367351, A367352, A367353, A367354. Starting with 3 is trivial, and those starting with 11, 12, 13 are essentially duplicates.
Sequence in context: A328814 A203433 A008562 * A041063 A105324 A179568
KEYWORD
nonn,base,fini
AUTHOR
N. J. A. Sloane, Nov 17 2023
STATUS
approved