OFFSET
0,2
FORMULA
a(n) = (1/(n+1)) * Sum_{k=0..n} (-1)^k * binomial(2*n+k+1,k) * binomial(5*n-k+3,n-k).
a(n) = (1/(n+1)) * Sum_{k=0..floor(n/2)} binomial(2*n+k+1,k) * binomial(3*n-2*k+1,n-2*k). - Seiichi Manyama, Jan 18 2024
a(n) = (1/(n+1)) * [x^n] 1/( (1+x)^2 * (1-x)^4 )^(n+1). - Seiichi Manyama, Feb 16 2024
D-finite with recurrence 41287680*n*(4*n+3)*(2*n+1) *(2*n-1) *(101600834504882*n -79530504768063) *(4*n+1)*(n+1)*a(n) -2048*n*(2*n-1) *(434506669234595351728*n^5 +44263551729813272744*n^4 -141669451985575941466*n^3 -268951240644423601763*n^2 +134606020676490900438*n -20668707583222185981)*a(n-1) +8*(-398564930699101536727520*n^7 +543141971021842664782320*n^6 +837332804222429331454882*n^5 -2219966207175180712139775*n^4 +2126251388322307117458940*n^3 -1338986566696277643223185*n^2 +555014916985484581653258*n -99934175131659030433320)*a(n-2) +7*(433107331515621433*n -223378841061948614)*(7*n-11) *(7*n-15)*(7*n-12) *(7*n-9)*(7*n-13) *(7*n-10)*a(n-3)=0. - R. J. Mathar, Dec 02 2025
PROG
(PARI) a(n) = sum(k=0, n, (-1)^k*binomial(2*n+k+1, k)*binomial(5*n-k+3, n-k))/(n+1);
(SageMath)
def A365855(n):
h = binomial(5*n + 3, n) * hypergeometric([-n, 2*n + 2], [-5 * n - 3], -1) / (n + 1)
return simplify(h)
print([A365855(n) for n in range(23)]) # Peter Luschny, Sep 20 2023
CROSSREFS
KEYWORD
nonn
AUTHOR
Seiichi Manyama, Sep 20 2023
STATUS
approved
