|
|
A365822
|
|
List the positive integers but erase commas between terms if the digits just before and just after the comma have the same parity.
|
|
2
|
|
|
1, 2, 3, 4, 5, 6, 7, 8, 910, 1112, 1314, 1516, 1718, 19, 2021, 2223, 2425, 2627, 282930, 3132, 3334, 3536, 3738, 39, 4041, 4243, 4445, 4647, 484950, 5152, 5354, 5556, 5758, 59, 6061, 6263, 6465, 6667, 686970, 7172, 7374, 7576, 7778, 79, 8081, 8283, 8485, 8687, 888990, 9192, 9394, 9596, 9798, 99100, 101102
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,2
|
|
COMMENTS
|
Erase a comma if the last digit of previous term and first digit of the following term have the same parity.
|
|
LINKS
|
|
|
EXAMPLE
|
1112 is in the sequence. We can check by looking at where 11 and 12 appear in the list of natural numbers {..., 10, 11, 12, 13, ...}. The digits that flank the comma in the pair (10,11) are {0,1}, which have opposite parity, so we keep the comma between 10 and 11. This gives {..., <--10, 11-->, ...} [the <-- --> arrows indicate the possibility of more digits to the left and right. Note that 910 is also a member!]. Checking the flanking digits in the pair (11,12), we see that {1,1} have the same parity, so the comma is deleted there to give {..., <--10, 1112-->, ...}. We must keep checking additional pairs to the right until we find a comma. (12,13) has flanking digits {2,1} with opposite parity, so no comma is deleted. Now we see that 1112 is a member, since {..., <--10, 1112, 13-->, ...}.
|
|
MATHEMATICA
|
nn = 120; j = {0}; Rest@ Reap[Do[Set[k, IntegerDigits[n]]; If[Mod[Last[j], 2] == Mod[First[k], 2], j = Join[j, k], Sow[FromDigits[j]]; j = k], {n, nn}] ][[-1, 1]] (* Michael De Vlieger, Nov 24 2023 *)
|
|
PROG
|
(Python)
from itertools import count, islice
def agen():
cat = ""
for i in count(1):
s = str(i)
if cat != "" and int(cat[-1])%2 != int(s[0])%2:
yield int(cat)
cat = ""
cat += s
|
|
CROSSREFS
|
|
|
KEYWORD
|
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|