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A362721
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Number of numbers k, 1 <= k <= n, such that pi(k) = pi(n-k+1).
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1
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1, 0, 1, 0, 1, 2, 1, 0, 1, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3, 4, 5, 6, 5, 4, 3, 2, 1, 0, 1, 2, 1, 0, 1, 2, 3, 4, 5, 6, 5, 4, 3, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3
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OFFSET
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1,6
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LINKS
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FORMULA
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a(n) = Sum_{k=1..n} [pi(k) = pi(n-k+1)], where pi is the prime counting function (A000720) and [ ] is the Iverson bracket.
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EXAMPLE
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There are two cases for a(6) due to symmetry, namely k=3: pi(3) = 2 = pi(6-3+1) and k=4: pi(4) = 2 = pi(6-4+1).
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MATHEMATICA
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Table[Sum[KroneckerDelta[PrimePi[n - k + 1], PrimePi[k]], {k, n}], {n, 100}]
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PROG
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(PARI) a(n) = sum(k=1, n, primepi(k) == primepi(n-k+1)); \\ Michel Marcus, May 01 2023
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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