OFFSET
3,1
FORMULA
a(n) = 2^n - A056007(n). - Kevin Ryde, Oct 13 2022
a(n) = A116601(n+2)^2. - Michel Marcus, Oct 13 2022
MATHEMATICA
Array[Floor[Sqrt[2^# - 1]]^2 &, 33, 3] (* Michael De Vlieger, Oct 11 2022 *)
PROG
(PARI) for (n=3, 35, forstep (k2=2^n-1, 2^(n-1), -1, if (issquare(k2), print1(k2, ", "); break)))
(PARI) a(n) = if(n%2 == 1, (sqrt(1<<n)\1)^2, ((1 << (n\2)) - 1)^2) \\ David A. Corneth, Oct 11 2022
(Python)
from math import isqrt
def A357754(n): return (isqrt((1<<n)-1) if n&1 else (1<<(n>>1))-1)**2 # Chai Wah Wu, Oct 13 2022
CROSSREFS
KEYWORD
nonn,base,easy
AUTHOR
Hugo Pfoertner, Oct 11 2022
STATUS
approved