A357506 a(n) = A005258(n)^3 * A005258(n-1).

27, 20577, 60353937, 287798988897, 1782634331587527, 13011500170881726987, 106321024671550496694837, 943479109706472533832704097, 8916177779855571182824077866307, 88547154924474394601268826256953077, 915376390434997094066775480671975209017

Offset

1,1

Comments

The Apéry numbers B(n) = A005258(n) satisfy the supercongruences B(p) == 3 (mod p^3) and B(p-1) == 1 (mod p^3) for all primes p >= 5 (see, for example, Straub, Example 3.4). It follows that a(p) == 27 (mod p^3) for all primes p >= 5. We conjecture that, in fact, the stronger congruence a(p) == 27 (mod p^5) holds for all primes p >= 3 (checked up to p = 251). Compare with the congruence B(p) + B(p-1) == 4 (mod p^5) conjectured to hold for all primes p >= 5. See A352655.

Conjecture: for r >= 2, a(p^r) == a(p^(r-1)) ( mod p^(3*r+3) ) for all primes p >= 5. - Peter Bala, Oct 13 2022

Links

Table of n, a(n) for n=1..11.

Armin Straub, Multivariate Apéry numbers and supercongruences of rational functions, arXiv:1401.0854 [math.NT] (2014).

Example

Example of a supercongruence:
a(7) - a(1) = 106321024671550496694837 - 27 = 2*(3^3)*5*(7^5)* 11*18143* 117398731273 == 0 (mod 7^5)

Maple

A005258 := n -> add(binomial(n, k)^2*binomial(n+k, k), k = 0..n):
seq(A005258(n)^3*A005258(n-1), n = 1..20);

Crossrefs

Cf. A005258, A212334, A339946, A352655, A357507, A357508, A357509.

Sequence in context: A111415 A036534 A167731 * A343692 A201369 A036529

Adjacent sequences: A357503 A357504 A357505 * A357507 A357508 A357509

Keyword

nonn,easy

Author

Peter Bala, Oct 01 2022

Status

approved