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A356511
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Total number of distinct numbers that can be obtained by starting with 1 and applying the "Choix de Bruxelles", version 2 operation at most n times in duodecimal (base 12).
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1
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1, 2, 3, 4, 5, 9, 19, 45, 107, 275, 778, 2581, 10170, 45237, 222859, 1191214, 6887258, 42894933, 287397837
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OFFSET
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0,2
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LINKS
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EXAMPLE
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For n=4, the a(4) = 5 numbers obtained are (in base 12): 1, 2, 4, 8, 14.
For n=5, they expand to a(5) = 9 numbers (in base 12): 1, 2, 4, 8, 12, 14, 18, 24, 28.
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PROG
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(Python) See links
(Python)
from itertools import islice
from sympy.ntheory import digits
def fd12(d): return sum(12**i*di for i, di in enumerate(d[::-1]))
def cdb2(n):
d, out = digits(n, 12)[1:], {n}
for l in range(1, len(d)+1):
for i in range(len(d)+1-l):
if d[i] == 0: continue
t = fd12(d[i:i+l])
out.add(fd12(d[:i] + digits(2*t, 12)[1:] + d[i+l:]))
if t&1 == 0:
out.add(fd12(d[:i] + digits(t//2, 12)[1:] + d[i+l:]))
return out
def agen():
reach, expand = {1}, [1]
while True:
yield len(reach)
newreach = {r for q in expand for r in cdb2(q) if r not in reach}
reach |= newreach
expand = list(newreach)
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CROSSREFS
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KEYWORD
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nonn,more,base
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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