|
|
A353238
|
|
Perfect powers that are divisible by 3.
|
|
2
|
|
|
9, 27, 36, 81, 144, 216, 225, 243, 324, 441, 576, 729, 900, 1089, 1296, 1521, 1728, 1764, 2025, 2187, 2304, 2601, 2916, 3249, 3375, 3600, 3969, 4356, 4761, 5184, 5625, 5832, 6084, 6561, 7056, 7569, 7776, 8100, 8649, 9216, 9261, 9801, 10404, 11025, 11664, 12321
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
Terms are multiples of 9, so that a(n) == 0 (mod 9) (since no perfect power divisible by 3 can have a 3-adic valuation below 2).
|
|
LINKS
|
|
|
FORMULA
|
a(n) has the form (3*m)^k for some positive integer m := m(n) and some k > 1.
Sum_{n>=1} 1/a(n) = -Sum_{k>=2} mu(k)*zeta(k)/3^k = 0.2306128559... - Amiram Eldar, Jul 02 2022
|
|
EXAMPLE
|
36 is a term since 36 = (2*3)^2 is a power of a multiple of 3.
|
|
MAPLE
|
q:= n-> igcd(seq(i[2], i=ifactors(n)[2]))>1:
|
|
MATHEMATICA
|
Select[9*Range[1400], GCD @@ FactorInteger[#][[All, 2]] > 1 &]
|
|
PROG
|
(PARI) isok(k) = ispower(k) && !(k % 3); \\ Michel Marcus, May 02 2022
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|