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EXAMPLE
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E.g.f.: A(x) = 1 + x - 4*x^2/2! + 20*x^3/3! - 224*x^4/4! + 3392*x^5/5! - 67232*x^6/6! + 1629728*x^7/7! - 46799104*x^8/8! + ...
such that A(x) = (1-x) * exp(2*x/A(x)), where
exp(2*x/A(x)) = 1 + 2*x + 20*x^3/3! - 144*x^4/4! + 2672*x^5/5! - 51200*x^6/6! + 1271328*x^7/7! - 36628480*x^8/8! + ...
Related series.
The e.g.f. A(x) satisfies A( x/(exp(-2*x) + x) ) = 1/(exp(-2*x) + x), where
1/(exp(-2*x) + x) = 1 + x - 2*x^2/2! - 10*x^3/3! + 24*x^4/4! + 312*x^5/5! - 560*x^6/6! + ... + A336958(n)*(-x)^n/n! + ...
Related table.
Another defining property of the e.g.f. A(x) is illustrated here.
The table of coefficients of x^k/k! in A(x)^n begins:
n=1: [1, 1, -4, 20, -224, 3392, -67232, 1629728, ...];
n=2: [1, 2, -6, 16, -192, 2944, -58880, 1434752, ...];
n=3: [1, 3, -6, -6, -48, 1296, -29664, 776544, ...];
n=4: [1, 4, -4, -40, 88, 128, -7424, 263936, ...];
n=5: [1, 5, 0, -80, 120, 280, -320, 38720, ...];
n=6: [1, 6, 6, -120, -24, 1872, -3312, 768, ...];
n=7: [1, 7, 14, -154, -392, 4424, -3920, -22288, ...];
...
from which we can illustrate that the partial sum of coefficients of x^k, k=0..n, in A(x)^n equals zero, for n > 1, as follows:
n=1: 2 = 1 + 1;
n=2: 0 = 1 + 2 + -6/2!;
n=3: 0 = 1 + 3 + -6/2! + -6/3!;
n=4: 0 = 1 + 4 + -4/2! + -40/3! + 88/4!;
n=5: 0 = 1 + 5 + 0/2! + -80/3! + 120/4! + 280/5!;
n=6: 0 = 1 + 6 + 6/2! + -120/3! + -24/4! + 1872/5! + -3312/6!;
n=7: 0 = 1 + 7 + 14/2! + -154/3! + -392/4! + 4424/5! + -3920/6! + -22288/7!;
...
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