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A349766
Numbers of the form 2*t^2 - 4 when t > 1 is a term in A001541.
2
14, 574, 19598, 665854, 22619534, 768398398, 26102926094, 886731088894, 30122754096398, 1023286908188734, 34761632124320654, 1180872205318713598, 40114893348711941774, 1362725501650887306814, 46292552162781456489998, 1572584048032918633353214, 53421565080956452077519374
OFFSET
1,1
COMMENTS
Equivalently: integers k such that k$ / (k/2+1)! and k$ / (k/2+2)! are both squares when A000178 (k) = k$ = 1!*2!*...*k! is the superfactorial of k (see A348692 for further information).
The 3 subsequences of A349081 are A035008, A139098 and this one.
LINKS
Rick Mabry and Laura McCormick, Square products of punctured sequences of factorials, Gaz. Aust. Math. Soc., 2009, No. 35, Vol. 2, pages 346-352.
FORMULA
a(n) = 2*(cosh(2*n*arcsinh(1)))^2 - 4.
a(n) = 16*A001110(n) - 2. - Hugo Pfoertner, Dec 04 2021
Sum_{n>=1} 1/a(n) = (1 - 1/sqrt(2))/4. - Amiram Eldar, Dec 11 2025
From Elmo R. Oliveira, Apr 12 2026: (Start)
a(n) = 35*a(n-1) - 35*a(n-2) + a(n-3) for n >= 4.
G.f.: 2*x*(7 + 42*x - x^2)/((1 - x)*(1 - 34*x + x^2)). (End)
E.g.f.: 2 - 3*exp(x) + exp(17*x)*cosh(12*sqrt(2)*x). - Stefano Spezia, Apr 12 2026
EXAMPLE
A001541(1) = 3, then for t = 3, 2*t^2-4 = 14; also for k = 14, 14$ / 8! = 1309248519599593818685440000000^2 and 14$ / 9! = 436416173199864606228480000000^2. Hence, 14 is a term.
MAPLE
with(orthopoly):
sequence = (2*T(n, 3)^2-4, n=1..20);
MATHEMATICA
(2*#^2 - 4) & /@ LinearRecurrence[{6, -1}, {3, 17}, 17] (* Amiram Eldar, Dec 04 2021 *)
LinearRecurrence[{35, -35, 1}, {14, 574, 19598}, 17] (* Ray Chandler, Mar 01 2024 *)
PROG
(PARI) a(n) = my(t=subst(polchebyshev(n), 'x, 3)); 2*t^2-4; \\ Michel Marcus, Dec 04 2021
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Bernard Schott, Dec 04 2021
STATUS
approved