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A348845
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Part two of the trisection of A017101: a(n) = 11 + 24*n.
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2
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11, 35, 59, 83, 107, 131, 155, 179, 203, 227, 251, 275, 299, 323, 347, 371, 395, 419, 443, 467, 491, 515, 539, 563, 587, 611, 635, 659, 683, 707, 731, 755, 779, 803, 827, 851, 875, 899, 923, 947, 971, 995, 1019, 1043, 1067
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OFFSET
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0,1
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COMMENTS
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The trisection of A017101 = {3 + 8*k}_{k>=0} gives 3*A017077 = {3*(1 + 12*n)}_{n>=0}, {a(n)}_{n >= 0} and A350051 = {19 + 24*n}_{n>=0}. These three sequences are congruent to 3 modulo 8 and to 3, 5, and 1 modulo 6, respectively.
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LINKS
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FORMULA
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a(n) = 11 + 24*n = 11 + A008606(n), for n >= 0
a(n) = 2*a(n-1) - a(n-2), for n >= 1, with a(-1) = -13, a(0) = 11.
G.f.: (11 + 13*x)/(1-x)^2.
E.g.f.: (11 + 24*x)*exp(x).
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MATHEMATICA
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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