login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A348599
Irregular triangle T(n,k) where row n is the partition of n with the least number of 3-smooth parts such that the product of parts is maximal.
3
1, 2, 3, 4, 3, 2, 6, 4, 3, 8, 9, 6, 4, 8, 3, 12, 9, 4, 8, 6, 9, 6, 16, 9, 8, 18, 16, 3, 12, 8, 12, 9, 16, 6, 9, 8, 6, 24, 16, 9, 18, 8, 27, 16, 12, 27, 2, 18, 12, 27, 4, 32, 24, 9, 18, 16, 27, 8, 36, 36, 1, 32, 6, 27, 12, 24, 16, 32, 9, 24, 18, 27, 16, 32, 12, 27, 18
OFFSET
1,2
COMMENTS
Let k = 2^a * 3^b be a part such that n is the sum of at least one such k. Then we may represent k at (a,b) on a Cartesian grid. In Dimitrov, et al., these k are known as "digits" in a 2-dimensional number base system. Since these partitions have the least number of parts (digits) in order to represent n, in Dimitrov this is called a "canonic form" for n in base (2,3).
These numbers represent an extreme representation where the digits tend to be placed close together.
REFERENCES
Vassil Dimitrov, Graham Jullien, and Roberto Muscedere, Multiple Number Base System Theory and Applications, 2nd ed., CRC Press (2012), 35-39.
LINKS
Michael De Vlieger, Table of n, a(n) for n = 1..10093 (rows n = 1..3600, flattened)
Michael De Vlieger, Plot of parts in row n at (T(n,k), n), for n = 1..256.
Michael De Vlieger, Plot T(n,k) at (T(n,k), n) for n = 1..10000.
Michael De Vlieger, Annotated plot of m = A347860(n,k) and m = T(n,k) at (m, n) for n = 1..64, showing m in row n of this sequence in blue, m in row n of A347860 in red, but in black if these coincide.
FORMULA
A237442(n) = length of row n.
EXAMPLE
Triangle begins:
1;
2;
3;
4;
3, 2; (product larger than (4,1))
6;
4, 3; (product larger than (6,1))
8;
9;
6, 4; (product greatest of {(9,1), (8,2), (6,4)})
8, 3; (product larger than (9,2))
12;
...
MATHEMATICA
nn = 45; s = Union@ Flatten@ Table[2^a*3^b, {a, 0, Log2[nn]}, {b, 0, Log[3, nn/(2^a)]}]; Table[Block[{k = 1, w, t = TakeWhile[ss, # <= n &]}, While[{} == Set[w, IntegerPartitions[n, {k}, t]], k++]; MaximalBy[w, Times @@ # &][[1]]], {n, nn}] ] // Flatten
CROSSREFS
KEYWORD
tabf,nonn
AUTHOR
Michael De Vlieger, Feb 23 2022
STATUS
approved