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A347053
a(n) is the smallest base-10 number greater than 1 such that when written in all bases from base 2 to base n its leading digit is 1.
1
2, 3, 4, 5, 78125, 67108864, 4747561509943, 4747561509943, 1123100968590805486067490785139871311149300510808491947285143687519677653346191462727898443913171541426176
OFFSET
2,1
COMMENTS
Each term is a power of a number <= n. The terms given in the data section are a(2) = 2, a(3) = 3, a(4) = 4, a(5) = 5, a(6) = 5^7 = 78125, a(7) = 4^13 = 67108864, a(8) = a(9) = 7^15 = 4747561509943, and a(10) = 6^135 = 1123...6176 (106 digits). The other known terms (too large to write in the data section) are a(11) = a(12) = 10^421 (422 digits), a(13) = 8^2144 = 1678...1296 (1937 digits), and a(14) = a(15) = 7^7081 = 1377...6007 (5985 digits).
Assuming a(16) exists it is greater than 10^21000.
a(16) = a(17) = 6^132847 = 1145...3136 (103376 digits); a(18) = 18^521808 = 1719...0576 (655012 digits); a(19) = a(20) = 7^1192509 = 1043...3607 (1007788 digits). - Jon E. Schoenfield, Aug 17 2021
a(21) = 3^6959688 (3320616 digits). - Scott R. Shannon and Jon E. Schoenfield_, Aug 20 2021
EXAMPLE
a(2) = 2 as 2 = 10_2, which has 1 as its leading digit.
a(3) = 3 as 3 = 11_2 = 10_3, each of which has 1 as its leading digit.
a(4) = 4 as 4 = 100_2 = 11_3 = 10_4, each of which has 1 as its leading digit.
a(5) = 5 as 5 = 101_2 = 12_3 = 11_4 = 10_5, each of which has 1 as its leading digit.
a(6) = 78125 as 78125 = 10011000100101101_2 = 10222011112_3 = 103010231_4 = 10000000_5 = 1401405_6, each of which has 1 as its leading digit.
a(7) = 67108864 as 67108864 = 100000000000000000000000000_2 = 11200021111001111_3 = 10000000000000_4 = 114134440424_5 = 10354213104_6 = 1443262444_7, each of which has 1 as its leading digit.
MATHEMATICA
Table[r=Range[2, n]; k=1; While[FreeQ[w=Union[First/@IntegerDigits[#^k, r]]&/@r, {1}], k++]; (First@@Position[w, {1}]+1)^k, {n, 2, 10}] (* Giorgos Kalogeropoulos, Aug 17 2021 *)
PROG
(Magma) I:=IntegerToString; N:=17; k:=2; e:=[]; P:=[]; for b in [2..N] do e[b]:=0; P[b]:=1; end for; B:=2; for n in [2..N] do OK:=false; while not OK do OK:=true; for b in [n..2 by -1] do if k ge P[b]*b then j:=Ilog(b, k div P[b]); if j gt 0 then e[b]+:=j; P[b]*:=b^j; end if; end if; if k div P[b] ne 1 then OK:=false; e[b]+:=1; P[b]*:=b; k:=P[b]; B:=b; break; end if; end for; end while; if IsPower(B) then _, r:=IsPower(B); E:=Ilog(r, k); else r:=B; E:=e[B]; end if; "a("*I(n)* ") = "*I(r)*"^"*I(E); end for; // Jon E. Schoenfield, Aug 19 2021
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Scott R. Shannon, Aug 14 2021
STATUS
approved