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A346149
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a(n) is the least integer k > 1 such that n^k + n + 1 is prime, or 0 if there is no such k.
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2
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2, 2, 2, 0, 2, 2, 0, 2, 3, 0, 4, 2, 0, 2, 2, 0, 2, 3, 0, 2, 2, 0, 9, 2, 0, 4, 2, 0, 3, 3, 0, 3, 2, 0, 15, 4, 0, 2, 3, 0, 2, 3, 0, 3, 6, 0, 4, 3, 0, 2, 9, 0, 3, 2, 0, 3, 2, 0, 2, 3, 0, 2, 73, 0, 12, 2, 0, 595, 2, 0, 2, 4, 0, 3, 2, 0, 2, 2, 0, 2, 7, 0, 3, 30, 0, 21, 3, 0, 2, 2, 0, 7, 67, 0, 3
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OFFSET
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1,1
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COMMENTS
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a(n) = 0 if n == 1 (mod 3) and n > 1.
Conjecture: a(n) > 0 otherwise.
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LINKS
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EXAMPLE
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a(9) = 3 because 9^3 + 9 + 1 = 739 is prime while 9^2+9+1 is not.
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MAPLE
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f:= proc(n) local i;
if n mod 3 = 1 then return 0 fi;
for i from 2 do if isprime(n^i+n+1) then return i fi od:
end proc:
f(1):= 2:
map(f, [$1..100]);
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PROG
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(PARI) a(n) = if ((n>1) && ((n%3)==1), 0, my(k=2); while (!isprime(n^k+n+1), k++); k); \\ Michel Marcus, Jul 07 2021
(Python)
from sympy import isprime
def a(n):
if n > 1 and n%3 == 1: return 0
k = 2
while not isprime(n**k + n + 1): k += 1
return k
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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