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A346070 Symbolic code for the corner turns in the Lévy dragon curve. 3
0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 0, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 1, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 0, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 2, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 0, 0, 1, 0, 2, 0, 1, 0 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,4
COMMENTS
We consider the Lévy dragon curve as constructed using line segments starting with an initial horizontal segment. The left endpoint of this segment is considered the beginning of the curve. Let L(k) denote the k-th iteration. It consists of 2^k segments and 2^k-1 corners. To get the next iteration, L(k+1), each of the segments in L(k) is replaced by two segments at right angles, always placing those segments towards the left of the segment in L(k).
Each iteration can be represented symbolically by a sequence consisting of the integers 0, 1, 2, and 3. One can imagine moving along the individual segments making up the curve starting at the left endpoint. A corner is labeled 0 if the curve makes a right turn there of 90 degrees, is labeled 2 if the curve makes a left turn of 90 degrees at that corner, is labeled 1 if the curve continues straight at that corner (0 degree turn), and is labeled 3 if the curve makes a 180-degree turn at that corner. The Lévy dragon is equal to the limit of L(k) as k goes to infinity.
It makes sense, as Knuth and Davis remarked in their article about the Heighway dragon, to express the Lévy dragon as the infinite sequence of 0's, 1's, 2's, and 3's obtained as each finite sequence for L(k) is extended to the limit. Then a(n) is the code for the behavior of the n-th corner in this infinite sequence.
REFERENCES
Paul Lévy, "Plane or space curves and surfaces consisting of parts similar to the whole," in Classics on Fractals, Gerald A. Edgar, Editor, Addison-Wesley, 181-239.
LINKS
Paul Lévy, Les courbes planes ou gauches et les surfaces composées de parties semblables au tout, Journal de l'École Polytechnique, July 1938 pages 227-247, and continued October 1938 pages 249-292, curve C.
Larry Riddle, First 31 terms, where R=0, S=1, L=2, and B=3.
FORMULA
a(n) = (A092412(n) - 1) mod 4.
a(2n-1) = 0, a(2n) = (a(n)+1) mod 4 = A092412(n).
Write n = k*4^m where k is not a multiple of 4. If k is odd, then a(n) = (2m) mod 4, and if k is even, then a(n) = (2m+1) mod 4.
a(n) = A007814(n) mod 4.
EXAMPLE
The first 15 terms correspond to iteration L(4) of the Levy dragon curve. These terms are 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0. The initial direction of the curve is 4*45=180 degrees (due west). The 15 terms indicate that the curve follows the pattern shown below.
-- -- -- --
| || |
-- --
| |
| |
-- * --
start
PROG
(Python)
def A346070(n): return (~n & n-1).bit_length() & 3 # Chai Wah Wu, Jul 01 2022
CROSSREFS
Cf. A092412 (essentially the same), A007814.
Sequence in context: A356945 A162590 A276424 * A191258 A254990 A191255
KEYWORD
easy,nonn
AUTHOR
Larry Riddle, Jul 04 2021
STATUS
approved

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Last modified April 16 14:46 EDT 2024. Contains 371749 sequences. (Running on oeis4.)