OFFSET
1,1
COMMENTS
Even numbers k for which A341624(k) = 1.
Even numbers whose closure under map x -> A003961(x) contains a primitive non-deficient number (one of the terms of A006039). Shifting each term k exactly A336835(k)-1 times with A003961 towards larger primes gives those numbers, but not in monotonic order, producing instead a permutation of A006039.
If there are any two terms, x and y, such that the other is a multiple of the other, then A336835(x) != A336835(y), and furthermore, for any term k present here, for all its proper divisors (d|k, d<k) it holds that A336835(d) < A336835(k), in other words, they reach the deficiency earlier (by prime shifting) than k itself.
LINKS
EXAMPLE
PROG
CROSSREFS
KEYWORD
nonn
AUTHOR
Antti Karttunen, Mar 20 2021
STATUS
approved