OFFSET
2,2
COMMENTS
Rows start at n = 2, and terms range from k = 2 to k = n. (When k = 1, there can be arbitrarily many lines.)
If a projective plane of order k-1 exists, then for n between k^2-k+1 and k^3-2k^2+3k-2 inclusive, T(n,k) = k^2-k+1. For higher n, T(n,k) = floor((n-1)/(k-1)).
EXAMPLE
For n = 10, k = 4, the unique arrangement with 5 lines (up to symmetry) is
1111000000
1000111000
0100100110
0010010101
0001001011
There are no such arrangements with 6 lines. Thus T(10,4) = 5.
These lines are in bijection with the sets of 4 polar axes on a dodecahedron whose endpoints form a cube.
Table begins:
n\k | 2 3 4 5 6 7 8 9
----+-----------------------
2 | 1;
3 | 3, 1;
4 | 3, 1, 1;
5 | 4, 2, 1, 1;
6 | 5, 4, 1, 1, 1;
7 | 6, 7, 2, 1, 1, 1;
8 | 7, 7, 2, 1, 1, 1, 1;
9 | 8, 7, 3, 2, 1, 1, 1, 1;
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Drake Thomas, Feb 26 2021
STATUS
approved