OFFSET
1,1
COMMENTS
Numbers k such that 2^k is a term: 8, 9, 10, 12, 13, 16, 18, 19, 20, 21, 22, 23, ... Are all sufficiently large powers of 2 terms? - Chai Wah Wu, Feb 24 2021
We don't know. From the comments in A341886, 2^k is a term if and only if t*2^(k+1)+1 is composite for t = 1, 2, 3. But we don't know if there are infinitely many Fermat primes. - Jianing Song, Feb 26 2021
All terms are divisible by 256. See my comment in A341886. - Jianing Song, Feb 27 2021
LINKS
Chai Wah Wu, Table of n, a(n) for n = 1..100
EXAMPLE
psi(2048) = 512 is divisible by 2*256, and there is no odd m < 2048 such that 2*256 | psi(m), so 256 is a term.
psi(47104) = 5632 is divisible by 2*2816, and there is no m < 47104 such that 2*2816 | psi(m), so 2816 is a term.
PROG
CROSSREFS
KEYWORD
nonn,hard
AUTHOR
Jianing Song, Feb 22 2021
EXTENSIONS
a(9)-a(20) from Michel Marcus, Feb 24 2021
a(21)-a(36) from Chai Wah Wu, Feb 24 2021
STATUS
approved
