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A338713
Number of numbers of the form i*n with 1 <= i <= n and tau(i*n) = 4.
2
0, 0, 1, 1, 2, 1, 3, 1, 1, 1, 4, 0, 5, 1, 1, 0, 6, 0, 7, 0, 1, 1, 8, 0, 1, 1, 1, 0, 9, 0, 10, 0, 1, 1, 1, 0, 11, 1, 1, 0, 12, 0, 13, 0, 0, 1, 14, 0, 1, 0, 1, 0, 15, 0, 1, 0, 1, 1, 16, 0, 17, 1, 0, 0, 1, 0, 18, 0, 1, 0, 19, 0, 20, 1, 0, 0, 1, 0, 21, 0, 0, 1, 22, 0, 1, 1, 1, 0, 23
OFFSET
1,5
LINKS
MATHEMATICA
Table[Count[Table[n i, {i, n}], _?(DivisorSigma[0, #]==4&)], {n, 90}] (* Harvey P. Dale, Jun 14 2022 *)
PROG
(PARI) a(n) = sum(i=1, n, numdiv(i*n)==4); \\ Michel Marcus, Nov 11 2020
(Python)
from collections import Counter
from sympy import factorint
def A338713(n):
f = Counter(factorint(n))
return sum(1 for i in range(1, n+1) if (l:=tuple((f+Counter(factorint(i))).values()))==(1, 1) or l==(3, )) # Chai Wah Wu, Oct 14 2023
CROSSREFS
tau is A000005.
For tau(i*n) = 2, 3, 6, see A010051, A296084, A338714.
Inspired by A333995.
Sequence in context: A320077 A325522 A006083 * A080301 A326674 A331184
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, Nov 11 2020
STATUS
approved