

A337854


a(n) is the smallest number that can be partitioned in exactly n ways as the sum of two Niven numbers.


2



0, 2, 4, 6, 8, 10, 51, 48, 72, 108, 126, 90, 138, 144, 120, 198, 162, 210, 216, 315, 240, 234, 306, 252, 372, 270, 546, 360, 342, 444, 414, 468, 420, 642, 450, 522, 540, 924, 612, 600, 666, 630, 888, 930, 756, 840, 882, 936, 972, 1098, 1215, 1026, 1212, 1080
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OFFSET

0,2


LINKS



EXAMPLE

a(0) = 0 because 0 cannot be written as the sum of two Niven numbers.
a(1) = 2 because 2 is uniquely written 2 = 1 + 1, with 1 in A005349.
a(2) = 4 because 4 = 1 + 3 = 2 + 2 and 1, 2, 3 are in A005349.
a(3) = 6 because 6 = 1 + 5 = 2 + 4 = 3 + 3 and 1, 2, 3, 4, 5 are terms in A005349.
a(6) = 51, because 51 = 1 + 50 = 3 + 48 = 6 + 45 = 9 + 42 = 21 + 30 = 24 + 27 and 1, 3, 6, 9, 21, 24, 27, 30, 42, 45, 48, 50 are terms in A005349.


MATHEMATICA

m = 1300; nivens = Select[Range[m], Divisible[#, Plus @@ IntegerDigits[#]] &]; a[n_] := Length[IntegerPartitions[n, {2}, nivens]]; mx = 54; s = Table[1, {mx}]; c = 0; n = 0; While[c < mx, i = a[n] + 1; If[i <= mx && s[[i]] < 0, c++; s[[i]] = n]; n++]; s (* Amiram Eldar, Sep 27 2020 *)


PROG

(Magma) a:=[]; niven:=func<nn mod &+Intseq(n) eq 0 >; for n in [0..55] do k:=0; while k le 10000 and #RestrictedPartitions(k, 2, {m:m in [1..k1] niven(m)}) ne n do k:=k+1; end while; Append(~a, k); end for; a;


CROSSREFS



KEYWORD

nonn,base


AUTHOR



STATUS

approved



