|
|
|
|
334639305, 1003917915, 1265809545, 1353106755, 1673196525, 2109682575, 2255177925, 2342475135, 2553826275, 2691663975, 2729952225, 2953555605, 2982654675, 3011753745, 3128150025, 3157249095, 3234846615, 3258330075, 3419140725, 3442113675, 3681032355, 3797428635, 3855626775, 4059320265, 4292112825, 4350310965
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
Provided that there are no odd perfect numbers, then applying A003961 to each term and sorting into ascending order gives A115414.
Apparently, all terms are divisible by 255255 = 3*5*7*11*13*17. - Hugo Pfoertner, Sep 24 2020
|
|
LINKS
|
|
|
PROG
|
(PARI)
A003961(n) = { my(f = factor(n)); for (i=1, #f~, f[i, 1] = nextprime(f[i, 1]+1)); factorback(f); };
isA337385(n) = if(!(n%2), 0, my(x=A003961(n)); (sigma(x)>=2*x));
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|