OFFSET
1,1
COMMENTS
This is conjectured to be a permutation of the positive integers.
One might enter the successive remainders as the sequence T, which would start with 1, 0, 3, 6, 9, 1, 5, 2, 4, 2, 3, 1, 8, 8, 1, 2, 5, 1, 3, 14, 2, 2, 3, 0, 2, 9, 2, 7, 1, 1, 3, 4, 31, 17, 1, 9,... We see that some remainders are > 9.
LINKS
Jean-Marc Falcoz, Table of n, a(n) for n = 1..10001
EXAMPLE
a(1)/a(2) = 10/3 = 3 with remainder 1;
a(3)/a(2) = 6/3 = 2 with remainder 0;
a(4)/a(3) = 9/6 = 1 with remainder 3;
a(5)/a(4) = 15/9 = 1 with remainder 6;
a(6)/a(5) = 24/15 = 1 with remainder 9;
a(6)/a(7) = 24/23 = 1 with remainder 1;
a(7)/a(8) = 23/18 = 1 with remainder 5; etc.
We see that the successive remainders 1,0,3,6,9,1,5,... are the successive digits of the sequence itself 10,3,6,9,15,24,23,...
CROSSREFS
KEYWORD
base,nonn
AUTHOR
Eric Angelini and Jean-Marc Falcoz, May 27 2020
STATUS
approved